Revised October 3, 1999 by inserting 1999 lecture numbers and
resetting links to 1999 lectures. I have attempted to make the
returns from the lectures to this page operational, but some may not
work properly until final editing of the lectures. .
I do not anticipate making any major changes to these
exercises, but some could occur when I edit the lectures.
You will be notified on the course notices page if changes are made.
Optional Virtual FlyLab Exercises
The exercises described below will help you to understand the principles
that are introduced in the various lectures about Mendelian genetics. The
exercises described below are matched to the course Lecture in which the
principles that they demonstrate are described. Links are also provided
to permit you to jump to the lecture notes, and to return to the
exercises from the lecture notes. Be
sure to read the course web page containing
Virtual FlyLab Information for Beginners
before attempting to do these exercises.
Menu of Available Exercises You may click on
the menu that follows to jump directly to the exercises for a particular
lecture, or you may scroll down. All of the exercises are on this
extended web page.
Lecture 21, Equal Segregation
Lecture 22, Independent Segregation
Lecture 24, Chi-Square Analysis
Lecture 25, Dominant Lethal Alleles
Lecture 26, Gene Interactions
Lecture 28, Sex-Linked Genes
Lecture 30, Linkage, Map Distance
Lecture 31, Three-Point Crosses, Gene Order
Lecture 21, Equal Segregation
This set of
exercises illustrates the principle of random segregation through the
use of monohybrid crosses of wild-type flies with strains that are homozygous
for autosomal (not sex linked) dominant or recessive mutations.
In this set of exercises, you will employ four different mutant strains,
brown eyes, ebony body, shaven
bristles, and lobed eyes.
For each of the strains, perform the following set of
experiments (parts of this exercise have been incorporated into
problem set #6).
- Mate a mutant female fly with a wild type male fly. Examine the F1
hybrids to determine whether the marker was dominant or recessive.
- Perform a test cross to verify your conclusions from experiment 1.
For recessive mutations, mate the F1 hybrid with the mutant parent and
examine the phenotypic distribution of the progeny. For dominant mutations,
mate the F1 hybrid with a wild type fly (wild type is recessive to a
dominant mutation) and examine the phenotypic distribution of the progeny.
In both cases, verify that the distributions are those expected from
test crosses. Also, be sure that you understand why you expect that
distribution from a test cross.
- Mate a male F1 hybrid with a female F1 hybrid to generate an F2
population. Examine the phenotypic ratio and verify that it is what is
expected for F2 progeny. Also be certain that you understand
the genetic mechanisms that give rise to that phenotypic ratio.
- Repeat steps 1 and 3 starting with a mutant male and a wild type
female to verify that these markers are autosomal. Because there is only
one X chromosome in males, sex-linked markers behave differently in the
two sexes, as we shall see when we get to lecture 28.
Go to Notes for Lecture 21
Return to Menu of Exercises
Lecture 22, Independent Assortment
This set of exercises illustrates the principle of independent
assortment through the use of crosses involving two or three
unlinked autosomal mutations.
- Place ebony body and shaven bristles in the
same parent (either sex) and
mate with a wild-type fly. Do a test cross of the F1 progeny with the
doubly-recessive parent and examine the phenotypic distribution of the
progeny. Verify that the results are consistent with the expectations
for such a test cross and be sure that you understand why the expectations
are what they are.
- Use the F1 progeny from step 1 to generate F2 progeny. Verify that the
phenotypic distribution is consistent with the expectation for an F2
dihybrid cross and be certain that you understand the basis for that
expectation.
- Place the two markers in a trans configuration in the
parental generation. Determine whether there is any affect on the F2
generation. Also be sure you understand why you cannot do a test cross
with the markers in a trans configuration.
- You know from the Lecture 21 exercises that lobed eyes
is dominant, and that ebony
body and shaven bristle mutations are recessive.
Construct a cross that will allow to do a test cross of the F1 triple
heterozygote for these three mutations. Remember that all of the recessive
alleles must be in the same parent to be able to do a test cross. Perform
the test cross and examine the phenotypic ratios. Be sure you understand
why these ratios come out the way they do.
- Mate the F1 hybrids from part 4 to obtain an F2 generation. Be certain
that you understand the theoretical basis for the phenotypic ratios that
are obtained.
Go to Notes for Lecture 22
Return to Menu of Exercises
Lecture 24, Chi-Square Analysis
The exercises that follow provide you with some opportunities to see
chi-square analysis in action without having to do the actual
numerical calculations.
Please note that some of the crosses have been deliberately selected to
yield unexpoected results that you will not be required to understand fully
until the principles that are involved are covered in future lectures. The
point at this time is that a chi-square analysis will not support
predictions based solely on the
elementary aspects of genetics that have already been covered in this course.
Thus, we will need to look for more complex explanations before the semester
is completed.
Whenever you
obtain the results of a cross with the Virtual FlyLab, one of the options
that is offered to you is to propose a hypothesis to explain the results,
which you can then analyze for goodness of fit using the chi-square formula.
Scroll down the results screen to "Possible Actions" and
click on the bar labeled "Propose and Test Hypotheses" (note that the formula
for chi-square is also on the bar).
The screen that comes up will allow
you either to work with the results including the sex of the progeny
flies or by scrolling down further, results excluding sex. To keep things
simple, this set of exercises excludes the sex of the progeny, which will
not become important until we begin to work with sex-linked loci.
In either case, you are asked to propose a theory to explain the results
and to insert your hypothetical ratios into a set of windows that follow
the observed ratios. For example, if you are looking at the F2 of a
monohybrid cross, the most likely theory to test would be a 3:1 ratio
of dominant phenotype to recessive. Click on each window and insert a
number that corresponds to your expectations. You must place numbers in all
of the windows for the data set you are working with. Then click on the bar
to perform the analysis.
The results that are shown will include the expected number (E) for each
observation, based on your hypothesis and the total number of flies
examined, the value (O-E)2/E for each observation, the
X2 value,
the number of degrees of freedom, and the probability that the amount of
deviation from your hypothesis could have occured by random chance.
There is also a
recommendation either to reject the hypothesis or not to reject the
hypothesis, based on the chi-square value and the number of degrees of
freedom. .
- Mate a male fly with brown eyes and ebony body to a wild-type female.
Mate the F1 progeny to generate an F2 generation. Test the hypothesis that
the results fit the expected 9:3:3:1 distribution for the F2 generation
of an unlinked dihybrid cross. If the Virtual FlyLab has the right
amount of randomness programmed into it, there should be a 1:20 chance that
the results of your first trial will fall outside the 0.05 confidence limit,
such that you will recive a recommendation to reject the hypothesis. If
this happens to you, start over with another set of crosses. The probability
should be very low (1/400) that you will have two independent crosses that
both fall outside the limits.
- Scroll to the bottom of the page that gave you the results of your
analysis of the data and click on the bar for proposing another hypothesis
for the same data. This time alter the expected ratio slightly (for example,
10:3:3:1) and run another analysis to see the effect on the chi-square value.
- Mate a female fly with curly wings to a wild type male. The progeny of both sexes will be half curly and half wild-type, which tells you that curly
is dominant and that the original curly-winged female fly and the
curly-wnged progeny are heterozygous. Mate the curly-winged F1 progeny and
examine the phenotypic distribution of the F2, which will come out about
2 curly:1 wild type. Test the hypothesis that this is really a random
deviation from 3:1. Also test the hypothesis that the ratio actually is
2:1. The reason for this unusual ratio is that the curly wings allele is
lethal when it is homozygous. This phenomenon will be discussed in lecture
25.
- Mate a male fly with brown eyes and dumpy wings with a wild type
female. Do a test cross of an F1 female double heterozygote with the
parental double recessive male. Analyze the results using the hypthesis of
a 1:1:1:1 ratio of the four possible genotypes in the test cross progeny.
These two genetic loci are on the same chromosome, but so far apart that
there is enough crossover so
they exhibit only a slight tendancy to stay linked together.
Try other ratios, such as 3:2:2:3 or 29:21:21:29 to see if you can find
one that will not be rejected by the chi-square analysis. We will begin
studying linkage in Lecture 30.
Go to Notes for Lecture 24
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Lecture 25, Dominant Lethal Alleles
Lecture 25 covers several distantly related topics, including
partial dominance, codominance, and dominant lethal alleles.
The only part of this lectue that can be illustrated with examples from
the Virtual FlyLab is the effect of dominant lethal alleles, which have
already been introduced in exercise 3 from Lecture 24.
- Produce F2 offspring of parental mutant strains crossed with wild type
to determine which of the following dominant mutations are lethal
when homozygous: Lobed eyes, Curly wings, Stubble Bristles, and
Star eyes. Remember that dominant lethal parents must be alive, and are
therefore heterozygous.
- Cross a curly winged male with a stubble bristled female. Explain the
phenotypic distribution of the offspring. (These two genetic loci are
not linked and undergo independent assortment. You may find it convenient
to construct a Punnett Square to explain the results of the cross)
- Cross a male double mutant from the F1 generation in part 2 with a
female double mutant. Construct a Punnett Square for the cross and
use it to predict the F2 phenotypic ratios. (Remember that being homozygous
for either of the lethal genes will be lethal). Do a Chi-square analysis
to test the validity of your predicted phenotypic ratios.
- Cross a curly winged fly with an ebony body fly. (Remember that
the dominant lethal Curly-winged parent will be heterozygous, whereas
the unlinked recessive ebony body parent will be homozygous. Mate the
male and female curly winged progeny of this cross, which will also be
heterozygous for ebony body. Use a forked line approach to predict the
phenotypes of the F2 progeny. Then do a chi-square analysis to test
the validity of your prediction. Be able to explain why this cross
yields a 6:3:2:1 ratio. If you have trouble with the forked line, first do
a Punnett square, and then convert your results to a forked line
diagram.
Go to Notes for Lecture 25
Return to Menu of Exercises
Lecture 26, Interaction Among Genes
The Virtual FlyLab can produce epistasis in two ways. The recessive
apterous and vestigial wing mutations will mask any mutations involving
wing shape, wing angle, or wing veins. The recessive eyeless mutation
will mask any of the eye color mutations. The exercises that follow have
been designed to avoid complications due to sex linkage or loci carried
on the same chromosome.
If you wish, you may substitute vestigial wings in place of apterous wings.
However, most of the other combinations that can be examined
using the Virtual FlyLab will yield more complex results due to
linkage of genes on the same chromosome or sex linkage. We are unable to
examine interactions among eye color mutations because the system only
allows us to work with one eye color mutation at a time.
- Mate a fly that has apterous wings with a fly that has radius incompletus
wings. Mate the F1 progeny to produce an F2 generation. Examine the
phenotypic distribution of the F2 progeny. Propose a theoretical
explanation for the distribution and use a Chi-square test to examine
goodness of fit (see the exercises for lecture 24 if you have forgotten
how to do Chi-square using the Virtual FlyLab). If you are having trouble
generating a hypothesis, construct a Punnett square for the F2 generation.
- Mate an eyeless fly with one that has brown eyes. Mate the F1 progeny to
produce an F2 generation. Propose a theoretical explanation for the
phenotypic distribution of the F2 progeny. Test the goodness of fit of
your prediction with a Chi-square test.
- Mate a fly that has apterous wings with a fly that has dichaete wings
(the last panel at the bottom of the selection menu). Observe the
phenotypic ratio of the offspring. (The Dichaete wings mutation is lethal
when homozygous, making this an extra interesting exercise). Mate the male
and female progeny that have dichaete wings. Examine the phenotypic
distribution of their progeny and propose an explanation for that
phenotypic ratio. Text the goodness of fit of your explanation with a
Chi-square analysis. You will probably need to construct a Punnett square
or a forked line diagram to develop your proposed explanation.
Go to Notes for Lecture 26
Return to Menu of Exercises
Lecture 28, Sex Linked Genes
- This exercise attempts to recreate some of the early experiments
done with sex linkage in Drosophila. You have found a male fly
with white eyes in your laboratory cultures.
a. Mate the white eyed male with a wild type female and observe the
progeny. What can you conclude about the mutation based on this
experiment alone.
b. Mate two F1 flies and observe the F2 progeny. What conclusions
can you reach from the phenotypic distributions?
c. Cross a heterozygous female with a white-eyed male. Interpret the
phenotypic distributions that are observed in male and female progeny
in terms of possible chromosomal mechanisms.
d. Mate a white-eyed female with a wild-type male. Interpret the
phenotypic distribution observed in the progeny.
e. Summarize the steps that must be completed to generate a true breeding
stock of white-eyed flies, starting with the original white-eyed male
and a wild-type female.
- Repeat as many of the above exercises as you can starting with a
Bar eyed male. At each step, be sure that you understand the differences
in the pattern of inheritance exhibited by the bar eyed and white eyed
mutations. .
- Compare the patterns of inheritance of bar eyes and lobed eyes.
a. What features do their inheritance patterns share in common?
b. How do their inheritance patterns differ?
c. Compare the F2 phenotypic distributions for a bar eyed male mated to
a wild type female and a lobed eyed male mated to a wild type female.
- Compare the patterns of inheritance for sable body and ebony body.
a. What features do their inheritance patterns share in common?
b. How do their inheritance patterns differ?
c. Compare the F2 phenotypic distributions for a ebony body male mated to
a wild type female and a sable body male mated to a wild type female.
- Based on the results you obtained in the two previous quesitons,
devise a simple procedure for distinguishing between each of the following
pairs. Perform the appropriate matings to verify that you procedure will
achieve the desired results.
a. Sex-linked dominant vs. sex-linked recessive.
b. Sex-linked dominant vs. autosomal dominant
c. Autosomal dominant vs. autosomal recessive
d. Autosomal recessive vs. sex-linked recessive.
- Determine which of the following loci are sex-linked and whether the
sex linked mutations are dominant or recessive. :
a. Tan Body
b. Black body
c. Bar eyes
d. Forked bristles
e. Singed bristles
f. Spineless bristles
g. Crossveinless wings
h. Dumpy wings
- Mate a male that has purple eyes and a sable body with a wild type female
and generate F2 progeny. Explain the phenotypic distribution in the
F2 generation in terms of chromosomal locations of the two loci.
Go to Notes for Lecture 28
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Lecture 30, Linkage, Map Distance
- Miniature wings and white eyes are both sex linked.
a. Mate a male that has miniature wings and white eyes to a wild-type
female. Test cross the F1 female with the parental male.
b. Mate a wild-type F1 male with a heterozygous F1 female.
c. Determine the phenotypic ratios of the male progeny.
d. Use the data from the male progeny to calculate the distance between
these two loci in centimorgans.
e. Mate a heterozygous F1 female with the hemizygous parental male and
repeat steps c and d examining only the male progeny of the cross.
f. Determine the phenotyopic ratios of the female progeny of the cross
in part e and calculate map distance based on those data.
g. Compare the three map distances that you have obtained. How much do they
differ. To what do you attribute the differences that you may have
observed?
- All of the genetic loci in this example are sex-linked.
a. Determine the distance in centimorgans from yellow body to each of
the following loci. white eyes, crossveinless wings, forked bristles,
miniature wings and singed bristles.
b. Construct a crude map of the X-chromosome, based on the assumption that
yellow body is at 0.0 map units.
c. Determine the map distances between all nearest neighbors on the map
by doing appropriate crosses.
d. Compare the apparent map distance from yellow to the most distant
locus on your map based on direct measurement with that obtained by adding
together all of the intermediate distances.
e. Determine the map distance from white eyes to sable body and to tan body
(note that direct measurements cannot be made between body color mutations
using the Virtual Fly Lab, and that they might have problems in real life
because of interactions of the body color genes).
f. Use the data from part e to add sable body and tan body to the map
you have constructed.
g. Determine the distances from sable body and tan body to their nearest
neighbors.
h. Perform the necessary crosses to add Bar eues to your map, keeping in
mind that it is dominant.
Go to Notes for Lecture 30
Return to Menu of Exercises
Lecture 31, Three-Point Crosses, Gene Order
- Three sex-linked mutations, white eyes, yellow body,
and miniature wings were used in the
earliest mapping experiments by Sturtevant and Morgan.
Mate a male fly that carries all three mutations with a wild type
female and then do a test cross on the F1 female.
a. Identify the paired recombinational events based on relative frequencies
of progeny. (If you work directly from the results page, you must first
combine males and females for each phenotype -- alternatively, you can go
to the Chi-square page where males and females are already added together.)
b. Determine the fraction of progeny that fall into each recombinational
class by dividing by the total number of flies counted.
c. Verify the identity of the parental pair (which you already know
from the original cross).
d. Identify the double recombinant pair.
e. Identify the middle genetic locus.
f. Identify the two single crossover pairs
g. Determine the corrected map distances between each of the possible pairings
of these three loci, adding in double crossover frequencies where
appropriate.
h. Reexamine your data, looking only at those classes of progeny in which
the two outside loci have recombined. This is equivalent to examining a
two point cross. How much does the apparent distance between these two
loci differ from the corrected distance, which is based on a three point
cross.
- Set up another experiment in which you can mate a female that is
heterozygous at all three of the loci in question 1 with a wild type male.
Repeat all of the exercises in question 1, looking only at male progeny of
the new cross. How closely do the results of the two experiments
correlate?
- The loci for sable body, bar eyes, and crossveinless wings
are also sex linked. Determine whether each of these mutations is
dominant or recessive, and then perform appropriate three point crosses
to determine their map positions relative to loci whose locations you
already know from problem 1 or earlier parts of this problem.
(Remember that wild-type is recessive to a dominant mutation. Also, be aware
that you can only use one mutation at a time from each category in
the Virtual FlyLab and plan your crosses accordingly.).
- Sepia eyes, radius incompletus wings, and ebony body are linked.
a. Determine the nature of each of the mutations.
b. Do two point crosses for each combination and construct a rough map
of the linkage group.
c. Do a three point cross and use the data to refine the two point map.
d. Calculate the interference to crossing over that was observed in
your two point cross.
e. Aristapedia antennae is very closely linked to one of these three
markers. Determine the nature of the AR mutation and see if you can place
it on your map relative to the other three mutations. (Remember that the
test parent must be all recessive, and that the fly that you select for
recombinational studies must be heterozygous for all of the markers you
are examining.)
- All of the makers in this exercise are recessive and carried on
chromosome II. Perform the following steps to obtain a partial map of
chromosome II and to examine the underestimation of map distance that
occurs in direct measurements between distant markers. Note that VFL
can only work with one eye color mutation at a time. Also, vestigial
wings and apterous wings cannot be used in the same cross. In addition,
these two mutations are epistatic to wing shape mutations.
a. Measure the distance from purple eyes to apterous wings in a two
point cross.
b. Use a three point cross to identify the middle locus and measure
apparent map distance among black body, apterous wings and purple eyes.
c. Use a three point cross to identify the middle locus and measure
apparent map distances among dumpy wings, black body, and purple eyes.
d. Use a three point cross to identify the middle locus and measure
apparent map distances among apterous wings, black body, and brown eyes.
(If you wish to shorten this exercise, you may skip to part g at this
time. However, doing so will reduce the accuracy of your final result
by reducing the number of intermediate measurements available.)
e. Use a three point cross to identify the middle locus and measure
apparent map distances among brown eyes, curved wings, and black body.
f. Use a three point cross to identify the middle locus and measure
apparent map distance among curved wings, purple eyes, and black body.
g. Construct a map of chromosome II, using the intermediate distances
obtained in all of the exercises above. Use the map to determine the
distance between brown eyes and dumpy wings as accurately as you can.
h. Measure the distance from brown eyes to dumpy wings in a two point cross.
How do you reconcile the difference between this measurement and the
map distance obtained in part g?
i. If you wish to expand your map to include more markers, you can find
map locations for four additional chromosome II markers,
vestigial wings (recessive), Lobed Eyes (dominant, non lethal), Curly wings
(Dominant lethal), and Star eyes (Dominant lethal). If you do so, you may
wish to calculate total map distance from Star eyes to brown eyes and to
compare that distance to the value obtained in a two point cross involving
those two markers.
Go to Notes for Lecture 31
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